-16t^2+1600t-14400=0

Solution for -16t^2+1600t-14400=0 equation:

-16t^2+1600t-14400=0

a = -16; b = 1600; c = -14400;
Δ = b2-4ac
Δ = 16002-4·(-16)·(-14400)
Δ = 1638400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1638400}=1280$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1600)-1280}{2*-16}=\frac{-2880}{-32}
=+90
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1600)+1280}{2*-16}=\frac{-320}{-32}
=+10
$